Simplifying code (2)

11. Affectation with arithmetic operators can be simplifed with the following equivalences:

• x=x+v; <=> x += v; (idem for *, -, ...)
• x+=1; <=> x ++; (idem for *, -, ...)

Thus:

int sum(int n) {
	int result = 0;
	for (int counter=1; counter<=n; counter++) result += counter;
	return result;
}

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